C32H23ClF3N7O4
2 compounds have this formula on CompoundList.
- Molar mass
- 662.02g/mol
- Monoisotopic mass
- 661.1452Da
- Atoms
- 70
- Elements
- 6
- Rings plus double bonds
- 23
The formula C32H23ClF3N7O4 describes a molecule made of 32 carbon atoms, 23 hydrogen atoms, 1 chlorine atom, 3 fluorine atoms, 7 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3258.06%12.011 × 32 = 384.352 g/mol
- H Hydrogen × 233.50%1.008 × 23 = 23.184 g/mol
- Cl Chlorine × 15.35%35.45 × 1 = 35.450 g/mol
- F Fluorine × 38.61%18.998 × 3 = 56.994 g/mol
- N Nitrogen × 714.81%14.007 × 7 = 98.049 g/mol
- O Oxygen × 49.67%15.999 × 4 = 63.996 g/mol
Compounds with the formula C32H23ClF3N7O4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C32H23ClF3N7O4?
The molar mass of C32H23ClF3N7O4 is 662.02 g/mol, calculated from standard atomic weights for 32 carbon atoms, 23 hydrogen atoms, 1 chlorine atom, 3 fluorine atoms, 7 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 661.1452 Da.
How many compounds have the formula C32H23ClF3N7O4?
CompoundList lists 2 compounds with the molecular formula C32H23ClF3N7O4, including Egfr-IN-8, FXIa-IN-15. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C32H23ClF3N7O4?
C32H23ClF3N7O4 has a degree of unsaturation of 23. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.