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Molecular formula

C32H25ClN4O5

1 compound has this formula on CompoundList.

Molar mass
581.02g/mol
Monoisotopic mass
580.1513Da
Atoms
67
Elements
5
Rings plus double bonds
22

The formula C32H25ClN4O5 describes a molecule made of 32 carbon atoms, 25 hydrogen atoms, 1 chlorine atom, 4 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 3266.15%
    12.011 × 32 = 384.352 g/mol
  • H Hydrogen × 254.34%
    1.008 × 25 = 25.200 g/mol
  • Cl Chlorine × 16.10%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 49.64%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 513.77%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C32H25ClN4O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

2-Naphthalenecarboxamide, N-(5-chloro-2-methoxyphenyl)-3-hydroxy-4-[2-[2-methoxy-5-[(phenylamino)carbonyl]phenyl]diazenyl]- chemical structure, C32H25ClN4O5, CAS 67990-05-0
2-Naphthalenecarboxamide, N-(5-chloro-2-methoxyphenyl)-3-hydroxy-4-[2-[2-methoxy-5-[(phenylamino)carbonyl]phenyl]diazenyl]-
CAS 67990-05-0C32H25ClN4O5

Frequently asked questions

What is the molar mass of C32H25ClN4O5?

The molar mass of C32H25ClN4O5 is 581.02 g/mol, calculated from standard atomic weights for 32 carbon atoms, 25 hydrogen atoms, 1 chlorine atom, 4 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 580.1513 Da.

How many compounds have the formula C32H25ClN4O5?

CompoundList lists 1 compound with the molecular formula C32H25ClN4O5, including 2-Naphthalenecarboxamide, N-(5-chloro-2-methoxyphenyl)-3-hydroxy-4-[2-[2-methoxy-5-[(phenylamino)carbonyl]phenyl]diazenyl]-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C32H25ClN4O5?

C32H25ClN4O5 has a degree of unsaturation of 22. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.