C32H43FN6O10
1 compound has this formula on CompoundList.
- Molar mass
- 690.73g/mol
- Monoisotopic mass
- 690.3025Da
- Atoms
- 92
- Elements
- 5
- Rings plus double bonds
- 14
The formula C32H43FN6O10 describes a molecule made of 32 carbon atoms, 43 hydrogen atoms, 1 fluorine atom, 6 nitrogen atoms and 10 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3255.64%12.011 × 32 = 384.352 g/mol
- H Hydrogen × 436.28%1.008 × 43 = 43.344 g/mol
- F Fluorine × 12.75%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 612.17%14.007 × 6 = 84.042 g/mol
- O Oxygen × 1023.16%15.999 × 10 = 159.990 g/mol
Compounds with the formula C32H43FN6O10
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C32H43FN6O10?
The molar mass of C32H43FN6O10 is 690.73 g/mol, calculated from standard atomic weights for 32 carbon atoms, 43 hydrogen atoms, 1 fluorine atom, 6 nitrogen atoms and 10 oxygen atoms. The monoisotopic mass is 690.3025 Da.
How many compounds have the formula C32H43FN6O10?
CompoundList lists 1 compound with the molecular formula C32H43FN6O10, including Z-LEHD-fmk. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C32H43FN6O10?
C32H43FN6O10 has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.