C33H31ClF3NO3
1 compound has this formula on CompoundList.
- Molar mass
- 582.06g/mol
- Monoisotopic mass
- 581.1945Da
- Atoms
- 72
- Elements
- 6
- Rings plus double bonds
- 17
The formula C33H31ClF3NO3 describes a molecule made of 33 carbon atoms, 31 hydrogen atoms, 1 chlorine atom, 3 fluorine atoms, 1 nitrogen atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3368.10%12.011 × 33 = 396.363 g/mol
- H Hydrogen × 315.37%1.008 × 31 = 31.248 g/mol
- Cl Chlorine × 16.09%35.45 × 1 = 35.450 g/mol
- F Fluorine × 39.79%18.998 × 3 = 56.994 g/mol
- N Nitrogen × 12.41%14.007 × 1 = 14.007 g/mol
- O Oxygen × 38.25%15.999 × 3 = 47.997 g/mol
Compounds with the formula C33H31ClF3NO3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C33H31ClF3NO3?
The molar mass of C33H31ClF3NO3 is 582.06 g/mol, calculated from standard atomic weights for 33 carbon atoms, 31 hydrogen atoms, 1 chlorine atom, 3 fluorine atoms, 1 nitrogen atom and 3 oxygen atoms. The monoisotopic mass is 581.1945 Da.
How many compounds have the formula C33H31ClF3NO3?
CompoundList lists 1 compound with the molecular formula C33H31ClF3NO3, including 3-(3-(((2-Chloro-3-(trifluoromethyl)phenyl)methyl)(2,2-diphenylethyl)amino)propoxy)benzeneacetic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C33H31ClF3NO3?
C33H31ClF3NO3 has a degree of unsaturation of 17. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.