C34H38N8O9
1 compound has this formula on CompoundList.
- Molar mass
- 702.73g/mol
- Monoisotopic mass
- 702.2762Da
- Atoms
- 89
- Elements
- 4
- Rings plus double bonds
- 20
The formula C34H38N8O9 describes a molecule made of 34 carbon atoms, 38 hydrogen atoms, 8 nitrogen atoms and 9 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3458.11%12.011 × 34 = 408.374 g/mol
- H Hydrogen × 385.45%1.008 × 38 = 38.304 g/mol
- N Nitrogen × 815.95%14.007 × 8 = 112.056 g/mol
- O Oxygen × 920.49%15.999 × 9 = 143.991 g/mol
Compounds with the formula C34H38N8O9
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C34H38N8O9?
The molar mass of C34H38N8O9 is 702.73 g/mol, calculated from standard atomic weights for 34 carbon atoms, 38 hydrogen atoms, 8 nitrogen atoms and 9 oxygen atoms. The monoisotopic mass is 702.2762 Da.
How many compounds have the formula C34H38N8O9?
CompoundList lists 1 compound with the molecular formula C34H38N8O9, including LHRH (1-5) (free acid). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C34H38N8O9?
C34H38N8O9 has a degree of unsaturation of 20. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.