CompoundList
Molecular formula

C34H40N4O7

3 compounds have this formula on CompoundList.

Molar mass
616.72g/mol
Monoisotopic mass
616.2897Da
Atoms
85
Elements
4
Rings plus double bonds
17

The formula C34H40N4O7 describes a molecule made of 34 carbon atoms, 40 hydrogen atoms, 4 nitrogen atoms and 7 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 3466.22%
    12.011 × 34 = 408.374 g/mol
  • H Hydrogen × 406.54%
    1.008 × 40 = 40.320 g/mol
  • N Nitrogen × 49.08%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 718.16%
    15.999 × 7 = 111.993 g/mol
Look up another formula

Compounds with the formula C34H40N4O7

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 3 of 3 compounds

Frequently asked questions

What is the molar mass of C34H40N4O7?

The molar mass of C34H40N4O7 is 616.72 g/mol, calculated from standard atomic weights for 34 carbon atoms, 40 hydrogen atoms, 4 nitrogen atoms and 7 oxygen atoms. The monoisotopic mass is 616.2897 Da.

How many compounds have the formula C34H40N4O7?

CompoundList lists 3 compounds with the molecular formula C34H40N4O7, including Suc-Val-Pro-Phe-MNA, Irinotecan EP impurity K, 1,1-Dimethylethyl [2-(4'-{2-[(2S)-1-(2S)-3-methyl-2-({[(methyloxy)carbonyl]amino}butanoyl)-2-pyrrolidinyl]-1H-imidazol-4-yl}-4-biphenylyl)-2-oxoethyl]carbamate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C34H40N4O7?

C34H40N4O7 has a degree of unsaturation of 17. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.