CompoundList
Molecular formula

C35H39N5O5

5 compounds have this formula on CompoundList.

Molar mass
609.73g/mol
Monoisotopic mass
609.2951Da
Atoms
84
Elements
4
Rings plus double bonds
19

The formula C35H39N5O5 describes a molecule made of 35 carbon atoms, 39 hydrogen atoms, 5 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 3568.95%
    12.011 × 35 = 420.385 g/mol
  • H Hydrogen × 396.45%
    1.008 × 39 = 39.312 g/mol
  • N Nitrogen × 511.49%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 513.12%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C35H39N5O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 5 of 5 compounds

Frequently asked questions

What is the molar mass of C35H39N5O5?

The molar mass of C35H39N5O5 is 609.73 g/mol, calculated from standard atomic weights for 35 carbon atoms, 39 hydrogen atoms, 5 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 609.2951 Da.

How many compounds have the formula C35H39N5O5?

CompoundList lists 5 compounds with the molecular formula C35H39N5O5, including Ergocristine, Ergocristinine, Phe-Pro dipeptide isostere. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C35H39N5O5?

C35H39N5O5 has a degree of unsaturation of 19. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.