C35H52N7O19P
1 compound has this formula on CompoundList.
- Molar mass
- 905.81g/mol
- Monoisotopic mass
- 905.3056Da
- Atoms
- 114
- Elements
- 5
- Rings plus double bonds
- 14
The formula C35H52N7O19P describes a molecule made of 35 carbon atoms, 52 hydrogen atoms, 7 nitrogen atoms, 19 oxygen atoms and 1 phosphorus atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3546.41%12.011 × 35 = 420.385 g/mol
- H Hydrogen × 525.79%1.008 × 52 = 52.416 g/mol
- N Nitrogen × 710.82%14.007 × 7 = 98.049 g/mol
- O Oxygen × 1933.56%15.999 × 19 = 303.981 g/mol
- P Phosphorus × 13.42%30.974 × 1 = 30.974 g/mol
Compounds with the formula C35H52N7O19P
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C35H52N7O19P?
The molar mass of C35H52N7O19P is 905.81 g/mol, calculated from standard atomic weights for 35 carbon atoms, 52 hydrogen atoms, 7 nitrogen atoms, 19 oxygen atoms and 1 phosphorus atom. The monoisotopic mass is 905.3056 Da.
How many compounds have the formula C35H52N7O19P?
CompoundList lists 1 compound with the molecular formula C35H52N7O19P, including 5,6,7,8-Tetrahydrosarcinapterin. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C35H52N7O19P?
C35H52N7O19P has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.