CompoundList
Molecular formula

C35H54O8

14 compounds have this formula on CompoundList.

Molar mass
602.81g/mol
Monoisotopic mass
602.3819Da
Atoms
97
Elements
3
Rings plus double bonds
9

The formula C35H54O8 describes a molecule made of 35 carbon atoms, 54 hydrogen atoms and 8 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 3569.74%
    12.011 × 35 = 420.385 g/mol
  • H Hydrogen × 549.03%
    1.008 × 54 = 54.432 g/mol
  • O Oxygen × 821.23%
    15.999 × 8 = 127.992 g/mol
Look up another formula

Compounds with the formula C35H54O8

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 14 of 14 compounds

Frequently asked questions

What is the molar mass of C35H54O8?

The molar mass of C35H54O8 is 602.81 g/mol, calculated from standard atomic weights for 35 carbon atoms, 54 hydrogen atoms and 8 oxygen atoms. The monoisotopic mass is 602.3819 Da.

How many compounds have the formula C35H54O8?

CompoundList lists 14 compounds with the molecular formula C35H54O8, including Tetronasin, Cimiside E, 12-O-Decanoylphorbol-13-(2-methylbutyrate). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C35H54O8?

C35H54O8 has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.