C37H61N2O+4
We do not list any compound with this exact formula yet.
- Molar mass
- 549.91g/mol
- Atoms
- 101
- Elements
- 4
The formula C37H61N2O+4 describes a molecule made of 37 carbon atoms, 61 hydrogen atoms, 2 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3780.81%12.011 × 37 = 444.407 g/mol
- H Hydrogen × 6111.18%1.008 × 61 = 61.488 g/mol
- N Nitrogen × 25.09%14.007 × 2 = 28.014 g/mol
- O Oxygen × 12.91%15.999 × 1 = 15.999 g/mol
Compounds with the formula C37H61N2O+4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
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Frequently asked questions
What is the molar mass of C37H61N2O+4?
The molar mass of C37H61N2O+4 is 549.91 g/mol, calculated from standard atomic weights for 37 carbon atoms, 61 hydrogen atoms, 2 nitrogen atoms and 1 oxygen atom.