C38H40BN3O4
1 compound has this formula on CompoundList.
- Molar mass
- 613.56g/mol
- Monoisotopic mass
- 613.3112Da
- Atoms
- 86
- Elements
- 5
The formula C38H40BN3O4 describes a molecule made of 38 carbon atoms, 40 hydrogen atoms, 1 boron atom, 3 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3874.39%12.011 × 38 = 456.418 g/mol
- H Hydrogen × 406.57%1.008 × 40 = 40.320 g/mol
- B Boron × 11.76%10.81 × 1 = 10.810 g/mol
- N Nitrogen × 36.85%14.007 × 3 = 42.021 g/mol
- O Oxygen × 410.43%15.999 × 4 = 63.996 g/mol
Compounds with the formula C38H40BN3O4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C38H40BN3O4?
The molar mass of C38H40BN3O4 is 613.56 g/mol, calculated from standard atomic weights for 38 carbon atoms, 40 hydrogen atoms, 1 boron atom, 3 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 613.3112 Da.
How many compounds have the formula C38H40BN3O4?
CompoundList lists 1 compound with the molecular formula C38H40BN3O4, including 4-(4-Morpholinyl)-1-((4-morpholinylcarbonyl)oxy)pyridinium tetraphenylborate(1-). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.