C38H40O18
2 compounds have this formula on CompoundList.
- Molar mass
- 784.72g/mol
- Monoisotopic mass
- 784.2215Da
- Atoms
- 96
- Elements
- 3
- Rings plus double bonds
- 19
The formula C38H40O18 describes a molecule made of 38 carbon atoms, 40 hydrogen atoms and 18 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3858.16%12.011 × 38 = 456.418 g/mol
- H Hydrogen × 405.14%1.008 × 40 = 40.320 g/mol
- O Oxygen × 1836.70%15.999 × 18 = 287.982 g/mol
Compounds with the formula C38H40O18
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C38H40O18?
The molar mass of C38H40O18 is 784.72 g/mol, calculated from standard atomic weights for 38 carbon atoms, 40 hydrogen atoms and 18 oxygen atoms. The monoisotopic mass is 784.2215 Da.
How many compounds have the formula C38H40O18?
CompoundList lists 2 compounds with the molecular formula C38H40O18, including 6'''-Feruloylspinosin, Implexaflavone. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C38H40O18?
C38H40O18 has a degree of unsaturation of 19. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.