C39H42BN3O4
1 compound has this formula on CompoundList.
- Molar mass
- 627.59g/mol
- Monoisotopic mass
- 627.3268Da
- Atoms
- 89
- Elements
- 5
The formula C39H42BN3O4 describes a molecule made of 39 carbon atoms, 42 hydrogen atoms, 1 boron atom, 3 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3974.64%12.011 × 39 = 468.429 g/mol
- H Hydrogen × 426.75%1.008 × 42 = 42.336 g/mol
- B Boron × 11.72%10.81 × 1 = 10.810 g/mol
- N Nitrogen × 36.70%14.007 × 3 = 42.021 g/mol
- O Oxygen × 410.20%15.999 × 4 = 63.996 g/mol
Compounds with the formula C39H42BN3O4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C39H42BN3O4?
The molar mass of C39H42BN3O4 is 627.59 g/mol, calculated from standard atomic weights for 39 carbon atoms, 42 hydrogen atoms, 1 boron atom, 3 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 627.3268 Da.
How many compounds have the formula C39H42BN3O4?
CompoundList lists 1 compound with the molecular formula C39H42BN3O4, including 2-Methyl-4-(4-morpholinyl)-1-((4-morpholinylcarbonyl)oxy)pyridinium tetraphenylborate(1-). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.