C39H55N9O17
1 compound has this formula on CompoundList.
- Molar mass
- 921.91g/mol
- Monoisotopic mass
- 921.3716Da
- Atoms
- 120
- Elements
- 4
- Rings plus double bonds
- 17
The formula C39H55N9O17 describes a molecule made of 39 carbon atoms, 55 hydrogen atoms, 9 nitrogen atoms and 17 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3950.81%12.011 × 39 = 468.429 g/mol
- H Hydrogen × 556.01%1.008 × 55 = 55.440 g/mol
- N Nitrogen × 913.67%14.007 × 9 = 126.063 g/mol
- O Oxygen × 1729.50%15.999 × 17 = 271.983 g/mol
Compounds with the formula C39H55N9O17
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C39H55N9O17?
The molar mass of C39H55N9O17 is 921.91 g/mol, calculated from standard atomic weights for 39 carbon atoms, 55 hydrogen atoms, 9 nitrogen atoms and 17 oxygen atoms. The monoisotopic mass is 921.3716 Da.
How many compounds have the formula C39H55N9O17?
CompoundList lists 1 compound with the molecular formula C39H55N9O17, including Trypsinogen. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C39H55N9O17?
C39H55N9O17 has a degree of unsaturation of 17. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.