C39H66N4O15
2 compounds have this formula on CompoundList.
- Molar mass
- 830.97g/mol
- Monoisotopic mass
- 830.4525Da
- Atoms
- 124
- Elements
- 4
- Rings plus double bonds
- 9
The formula C39H66N4O15 describes a molecule made of 39 carbon atoms, 66 hydrogen atoms, 4 nitrogen atoms and 15 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3956.37%12.011 × 39 = 468.429 g/mol
- H Hydrogen × 668.01%1.008 × 66 = 66.528 g/mol
- N Nitrogen × 46.74%14.007 × 4 = 56.028 g/mol
- O Oxygen × 1528.88%15.999 × 15 = 239.985 g/mol
Compounds with the formula C39H66N4O15
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C39H66N4O15?
The molar mass of C39H66N4O15 is 830.97 g/mol, calculated from standard atomic weights for 39 carbon atoms, 66 hydrogen atoms, 4 nitrogen atoms and 15 oxygen atoms. The monoisotopic mass is 830.4525 Da.
How many compounds have the formula C39H66N4O15?
CompoundList lists 2 compounds with the molecular formula C39H66N4O15, including (22S)-22-Carboxy-1-((2,5-dioxo-1-pyrrolidinyl)oxy)-1,10,19,24-tetraoxo-3,6,12,15-tetraoxa-9,18,23-triazahentetracontan-41-oic acid, (R)-22-Carboxy-1-((2,5-dioxopyrrolidin-1-yl)oxy)-1,10,19,24-tetraoxo-3,6,12,15-tetraoxa-9,18,23-triazahentetracontan-41-oic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C39H66N4O15?
C39H66N4O15 has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.