C3H9Br2Sb
1 compound has this formula on CompoundList.
- Molar mass
- 326.67g/mol
- Monoisotopic mass
- 323.8109Da
- Atoms
- 15
- Elements
- 4
The formula C3H9Br2Sb describes a molecule made of 3 carbon atoms, 9 hydrogen atoms, 2 bromine atoms and 1 antimony atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 311.03%12.011 × 3 = 36.033 g/mol
- H Hydrogen × 92.78%1.008 × 9 = 9.072 g/mol
- Br Bromine × 248.92%79.904 × 2 = 159.808 g/mol
- Sb Antimony × 137.27%121.76 × 1 = 121.760 g/mol
Compounds with the formula C3H9Br2Sb
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C3H9Br2Sb?
The molar mass of C3H9Br2Sb is 326.67 g/mol, calculated from standard atomic weights for 3 carbon atoms, 9 hydrogen atoms, 2 bromine atoms and 1 antimony atom. The monoisotopic mass is 323.8109 Da.
How many compounds have the formula C3H9Br2Sb?
CompoundList lists 1 compound with the molecular formula C3H9Br2Sb, including Trimethylantimony(V) bromide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.