CompoundList
Molecular formula

C40H23Cl5N6O4

2 compounds have this formula on CompoundList.

Molar mass
828.91g/mol
Monoisotopic mass
826.0223Da
Atoms
78
Elements
5
Rings plus double bonds
30

The formula C40H23Cl5N6O4 describes a molecule made of 40 carbon atoms, 23 hydrogen atoms, 5 chlorine atoms, 6 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4057.96%
    12.011 × 40 = 480.440 g/mol
  • H Hydrogen × 232.80%
    1.008 × 23 = 23.184 g/mol
  • Cl Chlorine × 521.38%
    35.45 × 5 = 177.250 g/mol
  • N Nitrogen × 610.14%
    14.007 × 6 = 84.042 g/mol
  • O Oxygen × 47.72%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C40H23Cl5N6O4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C40H23Cl5N6O4?

The molar mass of C40H23Cl5N6O4 is 828.91 g/mol, calculated from standard atomic weights for 40 carbon atoms, 23 hydrogen atoms, 5 chlorine atoms, 6 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 826.0223 Da.

How many compounds have the formula C40H23Cl5N6O4?

CompoundList lists 2 compounds with the molecular formula C40H23Cl5N6O4, including Pigment Red 144, 2-Naphthalenecarboxamide, N,N'-(2-chloro-1,4-phenylene)bis[4-[(2,5-dichlorophenyl)azo]-6-hydroxy-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C40H23Cl5N6O4?

C40H23Cl5N6O4 has a degree of unsaturation of 30. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.