C40H36F10IrN4P
1 compound has this formula on CompoundList.
- Molar mass
- 985.93g/mol
- Monoisotopic mass
- 986.2147Da
- Atoms
- 92
- Elements
- 6
The formula C40H36F10IrN4P describes a molecule made of 40 carbon atoms, 36 hydrogen atoms, 10 fluorine atoms, 1 iridium atom, 4 nitrogen atoms and 1 phosphorus atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 4048.73%12.011 × 40 = 480.440 g/mol
- H Hydrogen × 363.68%1.008 × 36 = 36.288 g/mol
- F Fluorine × 1019.27%18.998 × 10 = 189.980 g/mol
- Ir Iridium × 119.50%192.22 × 1 = 192.220 g/mol
- N Nitrogen × 45.68%14.007 × 4 = 56.028 g/mol
- P Phosphorus × 13.14%30.974 × 1 = 30.974 g/mol
Compounds with the formula C40H36F10IrN4P
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C40H36F10IrN4P?
The molar mass of C40H36F10IrN4P is 985.93 g/mol, calculated from standard atomic weights for 40 carbon atoms, 36 hydrogen atoms, 10 fluorine atoms, 1 iridium atom, 4 nitrogen atoms and 1 phosphorus atom. The monoisotopic mass is 986.2147 Da.
How many compounds have the formula C40H36F10IrN4P?
CompoundList lists 1 compound with the molecular formula C40H36F10IrN4P, including Iridium(3+) ion bis(3,5-difluoro-2-(pyridin-2-yl)benzen-1-ide) 4-tert-butyl-2-(4-tert-butylpyridin-2-yl)pyridine hexafluoro-lambda5-phosphanuide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.