C40H65KO13
1 compound has this formula on CompoundList.
- Molar mass
- 793.04g/mol
- Monoisotopic mass
- 792.4062Da
- Atoms
- 119
- Elements
- 4
The formula C40H65KO13 describes a molecule made of 40 carbon atoms, 65 hydrogen atoms, 1 potassium atom and 13 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 4060.58%12.011 × 40 = 480.440 g/mol
- H Hydrogen × 658.26%1.008 × 65 = 65.520 g/mol
- K Potassium × 14.93%39.098 × 1 = 39.098 g/mol
- O Oxygen × 1326.23%15.999 × 13 = 207.987 g/mol
Compounds with the formula C40H65KO13
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C40H65KO13?
The molar mass of C40H65KO13 is 793.04 g/mol, calculated from standard atomic weights for 40 carbon atoms, 65 hydrogen atoms, 1 potassium atom and 13 oxygen atoms. The monoisotopic mass is 792.4062 Da.
How many compounds have the formula C40H65KO13?
CompoundList lists 1 compound with the molecular formula C40H65KO13, including Laidlomycin propionate potassium. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.