C42H34F16IrN4P
1 compound has this formula on CompoundList.
- Molar mass
- 1121.92g/mol
- Monoisotopic mass
- 1122.1895Da
- Atoms
- 98
- Elements
- 6
The formula C42H34F16IrN4P describes a molecule made of 42 carbon atoms, 34 hydrogen atoms, 16 fluorine atoms, 1 iridium atom, 4 nitrogen atoms and 1 phosphorus atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 4244.96%12.011 × 42 = 504.462 g/mol
- H Hydrogen × 343.05%1.008 × 34 = 34.272 g/mol
- F Fluorine × 1627.09%18.998 × 16 = 303.968 g/mol
- Ir Iridium × 117.13%192.22 × 1 = 192.220 g/mol
- N Nitrogen × 44.99%14.007 × 4 = 56.028 g/mol
- P Phosphorus × 12.76%30.974 × 1 = 30.974 g/mol
Compounds with the formula C42H34F16IrN4P
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
![(4,4'-Di-tert-butyl-2,2'-bipyridine)bis[3,5-difluoro-2-[5-trifluoromethyl-2-pyridinyl-kappaN)phenyl-kappaC]iridium(III) Hexafluorophosphate chemical structure, C42H34F16IrN4P, CAS 870987-63-6](/s/XFAXYKCDJPDUTA-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C42H34F16IrN4P?
The molar mass of C42H34F16IrN4P is 1121.92 g/mol, calculated from standard atomic weights for 42 carbon atoms, 34 hydrogen atoms, 16 fluorine atoms, 1 iridium atom, 4 nitrogen atoms and 1 phosphorus atom. The monoisotopic mass is 1122.1895 Da.
How many compounds have the formula C42H34F16IrN4P?
CompoundList lists 1 compound with the molecular formula C42H34F16IrN4P, including (4,4'-Di-tert-butyl-2,2'-bipyridine)bis[3,5-difluoro-2-[5-trifluoromethyl-2-pyridinyl-kappaN)phenyl-kappaC]iridium(III) Hexafluorophosphate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.