CompoundList
Molecular formula

C42H47N3O25

1 compound has this formula on CompoundList.

Molar mass
993.83g/mol
Monoisotopic mass
993.2499Da
Atoms
117
Elements
4
Rings plus double bonds
21

The formula C42H47N3O25 describes a molecule made of 42 carbon atoms, 47 hydrogen atoms, 3 nitrogen atoms and 25 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4250.76%
    12.011 × 42 = 504.462 g/mol
  • H Hydrogen × 474.77%
    1.008 × 47 = 47.376 g/mol
  • N Nitrogen × 34.23%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 2540.25%
    15.999 × 25 = 399.975 g/mol
Look up another formula

Compounds with the formula C42H47N3O25

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C42H47N3O25?

The molar mass of C42H47N3O25 is 993.83 g/mol, calculated from standard atomic weights for 42 carbon atoms, 47 hydrogen atoms, 3 nitrogen atoms and 25 oxygen atoms. The monoisotopic mass is 993.2499 Da.

How many compounds have the formula C42H47N3O25?

CompoundList lists 1 compound with the molecular formula C42H47N3O25, including Salmochelin S4. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C42H47N3O25?

C42H47N3O25 has a degree of unsaturation of 21. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.