CompoundList
Molecular formula

C42H63ClN10O7

2 compounds have this formula on CompoundList.

Molar mass
855.48g/mol
Monoisotopic mass
854.4570Da
Atoms
123
Elements
5
Rings plus double bonds
16

The formula C42H63ClN10O7 describes a molecule made of 42 carbon atoms, 63 hydrogen atoms, 1 chlorine atom, 10 nitrogen atoms and 7 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4258.97%
    12.011 × 42 = 504.462 g/mol
  • H Hydrogen × 637.42%
    1.008 × 63 = 63.504 g/mol
  • Cl Chlorine × 14.14%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 1016.37%
    14.007 × 10 = 140.070 g/mol
  • O Oxygen × 713.09%
    15.999 × 7 = 111.993 g/mol
Look up another formula

Compounds with the formula C42H63ClN10O7

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C42H63ClN10O7?

The molar mass of C42H63ClN10O7 is 855.48 g/mol, calculated from standard atomic weights for 42 carbon atoms, 63 hydrogen atoms, 1 chlorine atom, 10 nitrogen atoms and 7 oxygen atoms. The monoisotopic mass is 854.4570 Da.

How many compounds have the formula C42H63ClN10O7?

CompoundList lists 2 compounds with the molecular formula C42H63ClN10O7, including N-[(Benzyloxy)carbonyl]valyllysyllysyl-N~5~-(diaminomethylidene)-N-(4-methoxynaphthalen-2-yl)ornithinamide--hydrogen chloride (1/1), Cbz-Val-Lys-Lys-Arg-MNA.HCl. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C42H63ClN10O7?

C42H63ClN10O7 has a degree of unsaturation of 16. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.