C44H28MgN4
1 compound has this formula on CompoundList.
- Molar mass
- 637.04g/mol
- Monoisotopic mass
- 636.2164Da
- Atoms
- 77
- Elements
- 4
The formula C44H28MgN4 describes a molecule made of 44 carbon atoms, 28 hydrogen atoms, 1 magnesium atom and 4 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 4482.96%12.011 × 44 = 528.484 g/mol
- H Hydrogen × 284.43%1.008 × 28 = 28.224 g/mol
- Mg Magnesium × 13.82%24.305 × 1 = 24.305 g/mol
- N Nitrogen × 48.80%14.007 × 4 = 56.028 g/mol
Compounds with the formula C44H28MgN4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C44H28MgN4?
The molar mass of C44H28MgN4 is 637.04 g/mol, calculated from standard atomic weights for 44 carbon atoms, 28 hydrogen atoms, 1 magnesium atom and 4 nitrogen atoms. The monoisotopic mass is 636.2164 Da.
How many compounds have the formula C44H28MgN4?
CompoundList lists 1 compound with the molecular formula C44H28MgN4, including Mg(ii) meso-tetraphenylporphine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.