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Molecular formula

C44H57N7O6

4 compounds have this formula on CompoundList.

Molar mass
779.98g/mol
Monoisotopic mass
779.4370Da
Atoms
114
Elements
4
Rings plus double bonds
20

The formula C44H57N7O6 describes a molecule made of 44 carbon atoms, 57 hydrogen atoms, 7 nitrogen atoms and 6 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4467.76%
    12.011 × 44 = 528.484 g/mol
  • H Hydrogen × 577.37%
    1.008 × 57 = 57.456 g/mol
  • N Nitrogen × 712.57%
    14.007 × 7 = 98.049 g/mol
  • O Oxygen × 612.31%
    15.999 × 6 = 95.994 g/mol
Look up another formula

Compounds with the formula C44H57N7O6

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 4 of 4 compounds

6-(4-Aminobutyl)-12-benzyl-9-(1H-indol-3-ylmethyl)-3-(1-phenylmethoxyethyl)-1,4,7,10,13-pentazacycloicosane-2,5,8,11,14-pentone chemical structure, C44H57N7O6
6-(4-Aminobutyl)-12-benzyl-9-(1H-indol-3-ylmethyl)-3-(1-phenylmethoxyethyl)-1,4,7,10,13-pentazacycloicosane-2,5,8,11,14-pentone
C44H57N7O6
6-(4-Aminobutyl)-12-benzyl-3-(1-(benzyloxy)ethyl)-9-((1H-indol-3-yl)methyl)-1,4,7,10,13-pentaazacycloicosa-1,4,7,10,13-pentaene-2,5,8,11,14-pentol chemical structure, C44H57N7O6, CAS 84211-54-1
6-(4-Aminobutyl)-12-benzyl-3-(1-(benzyloxy)ethyl)-9-((1H-indol-3-yl)methyl)-1,4,7,10,13-pentaazacycloicosa-1,4,7,10,13-pentaene-2,5,8,11,14-pentol
CAS 84211-54-1C44H57N7O6
(3S,9R,12S)-6-(4-Aminobutyl)-12-benzyl-9-(1H-indol-3-ylmethyl)-3-[(1R)-1-phenylmethoxyethyl]-1,4,7,10,13-pentazacycloicosane-2,5,8,11,14-pentone chemical structure, C44H57N7O6
(3S,9R,12S)-6-(4-Aminobutyl)-12-benzyl-9-(1H-indol-3-ylmethyl)-3-[(1R)-1-phenylmethoxyethyl]-1,4,7,10,13-pentazacycloicosane-2,5,8,11,14-pentone
C44H57N7O6
(3S,6R,9S,12S)-6-(4-Aminobutyl)-12-benzyl-9-(1H-indol-3-ylmethyl)-3-[(1R)-1-phenylmethoxyethyl]-1,4,7,10,13-pentazacycloicosane-2,5,8,11,14-pentone chemical structure, C44H57N7O6
(3S,6R,9S,12S)-6-(4-Aminobutyl)-12-benzyl-9-(1H-indol-3-ylmethyl)-3-[(1R)-1-phenylmethoxyethyl]-1,4,7,10,13-pentazacycloicosane-2,5,8,11,14-pentone
C44H57N7O6

Frequently asked questions

What is the molar mass of C44H57N7O6?

The molar mass of C44H57N7O6 is 779.98 g/mol, calculated from standard atomic weights for 44 carbon atoms, 57 hydrogen atoms, 7 nitrogen atoms and 6 oxygen atoms. The monoisotopic mass is 779.4370 Da.

How many compounds have the formula C44H57N7O6?

CompoundList lists 4 compounds with the molecular formula C44H57N7O6, including 6-(4-Aminobutyl)-12-benzyl-9-(1H-indol-3-ylmethyl)-3-(1-phenylmethoxyethyl)-1,4,7,10,13-pentazacycloicosane-2,5,8,11,14-pentone, 6-(4-Aminobutyl)-12-benzyl-3-(1-(benzyloxy)ethyl)-9-((1H-indol-3-yl)methyl)-1,4,7,10,13-pentaazacycloicosa-1,4,7,10,13-pentaene-2,5,8,11,14-pentol, (3S,9R,12S)-6-(4-Aminobutyl)-12-benzyl-9-(1H-indol-3-ylmethyl)-3-[(1R)-1-phenylmethoxyethyl]-1,4,7,10,13-pentazacycloicosane-2,5,8,11,14-pentone. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C44H57N7O6?

C44H57N7O6 has a degree of unsaturation of 20. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.