CompoundList
Sign in
Molecular formula

C45H33F5N2O5

1 compound has this formula on CompoundList.

Molar mass
776.76g/mol
Monoisotopic mass
776.2310Da
Atoms
90
Elements
5
Rings plus double bonds
28

The formula C45H33F5N2O5 describes a molecule made of 45 carbon atoms, 33 hydrogen atoms, 5 fluorine atoms, 2 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4569.58%
    12.011 × 45 = 540.495 g/mol
  • H Hydrogen × 334.28%
    1.008 × 33 = 33.264 g/mol
  • F Fluorine × 512.23%
    18.998 × 5 = 94.990 g/mol
  • N Nitrogen × 23.61%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 510.30%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C45H33F5N2O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

N2-[(9H-Fluoren-9-ylmethoxy)carbonyl]-N-(triphenylmethyl)-L-glutamine 2,3,4,5,6-pentafluorophenyl ester chemical structure, C45H33F5N2O5, CAS 132388-65-9
N2-[(9H-Fluoren-9-ylmethoxy)carbonyl]-N-(triphenylmethyl)-L-glutamine 2,3,4,5,6-pentafluorophenyl ester
CAS 132388-65-9C45H33F5N2O5

Frequently asked questions

What is the molar mass of C45H33F5N2O5?

The molar mass of C45H33F5N2O5 is 776.76 g/mol, calculated from standard atomic weights for 45 carbon atoms, 33 hydrogen atoms, 5 fluorine atoms, 2 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 776.2310 Da.

How many compounds have the formula C45H33F5N2O5?

CompoundList lists 1 compound with the molecular formula C45H33F5N2O5, including N2-[(9H-Fluoren-9-ylmethoxy)carbonyl]-N-(triphenylmethyl)-L-glutamine 2,3,4,5,6-pentafluorophenyl ester. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C45H33F5N2O5?

C45H33F5N2O5 has a degree of unsaturation of 28. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.