CompoundList
Molecular formula

C49H54ClN4O10P

2 compounds have this formula on CompoundList.

Molar mass
925.41g/mol
Monoisotopic mass
924.3266Da
Atoms
119
Elements
6
Rings plus double bonds
25

The formula C49H54ClN4O10P describes a molecule made of 49 carbon atoms, 54 hydrogen atoms, 1 chlorine atom, 4 nitrogen atoms, 10 oxygen atoms and 1 phosphorus atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4963.60%
    12.011 × 49 = 588.539 g/mol
  • H Hydrogen × 545.88%
    1.008 × 54 = 54.432 g/mol
  • Cl Chlorine × 13.83%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 46.05%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 1017.29%
    15.999 × 10 = 159.990 g/mol
  • P Phosphorus × 13.35%
    30.974 × 1 = 30.974 g/mol
Look up another formula

Compounds with the formula C49H54ClN4O10P

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C49H54ClN4O10P?

The molar mass of C49H54ClN4O10P is 925.41 g/mol, calculated from standard atomic weights for 49 carbon atoms, 54 hydrogen atoms, 1 chlorine atom, 4 nitrogen atoms, 10 oxygen atoms and 1 phosphorus atom. The monoisotopic mass is 924.3266 Da.

How many compounds have the formula C49H54ClN4O10P?

CompoundList lists 2 compounds with the molecular formula C49H54ClN4O10P, including 3'-Cytidylic acid, N-benzoyl-5'-O-[bis(4-methoxyphenyl)phenylmethyl]-2'-deoxy-, mono(2-chlorophenyl) ester, compd. with N,N-diethylethanamine (1:1), 3'-Cytidylic acid, N-benzoyl-5'-O-[bis(4-methoxyphenyl)phenylmethyl]-2'-deoxy-, mono(4-chlorophenyl) ester, compd. with N,N-diethylethanamine (1:1). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C49H54ClN4O10P?

C49H54ClN4O10P has a degree of unsaturation of 25. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.