C4H4O12Zr
1 compound has this formula on CompoundList.
- Molar mass
- 335.29g/mol
- Monoisotopic mass
- 333.8750Da
- Atoms
- 21
- Elements
- 4
The formula C4H4O12Zr describes a molecule made of 4 carbon atoms, 4 hydrogen atoms, 12 oxygen atoms and 1 zirconium atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 414.33%12.011 × 4 = 48.044 g/mol
- H Hydrogen × 41.20%1.008 × 4 = 4.032 g/mol
- O Oxygen × 1257.26%15.999 × 12 = 191.988 g/mol
- Zr Zirconium × 127.21%91.224 × 1 = 91.224 g/mol
Compounds with the formula C4H4O12Zr
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C4H4O12Zr?
The molar mass of C4H4O12Zr is 335.29 g/mol, calculated from standard atomic weights for 4 carbon atoms, 4 hydrogen atoms, 12 oxygen atoms and 1 zirconium atom. The monoisotopic mass is 333.8750 Da.
How many compounds have the formula C4H4O12Zr?
CompoundList lists 1 compound with the molecular formula C4H4O12Zr, including Zirconium, (mu-(carbonato(2-)-kappaO:kappaO'))dihydroxydioxodi-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.