CompoundList
Molecular formula

C4H5ClF2N2S

2 compounds have this formula on CompoundList.

Molar mass
186.60g/mol
Monoisotopic mass
185.9830Da
Atoms
15
Elements
6
Rings plus double bonds
2

The formula C4H5ClF2N2S describes a molecule made of 4 carbon atoms, 5 hydrogen atoms, 1 chlorine atom, 2 fluorine atoms, 2 nitrogen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 425.75%
    12.011 × 4 = 48.044 g/mol
  • H Hydrogen × 52.70%
    1.008 × 5 = 5.040 g/mol
  • Cl Chlorine × 119.00%
    35.45 × 1 = 35.450 g/mol
  • F Fluorine × 220.36%
    18.998 × 2 = 37.996 g/mol
  • N Nitrogen × 215.01%
    14.007 × 2 = 28.014 g/mol
  • S Sulfur × 117.18%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C4H5ClF2N2S

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C4H5ClF2N2S?

The molar mass of C4H5ClF2N2S is 186.60 g/mol, calculated from standard atomic weights for 4 carbon atoms, 5 hydrogen atoms, 1 chlorine atom, 2 fluorine atoms, 2 nitrogen atoms and 1 sulfur atom. The monoisotopic mass is 185.9830 Da.

How many compounds have the formula C4H5ClF2N2S?

CompoundList lists 2 compounds with the molecular formula C4H5ClF2N2S, including 4-(Difluoromethyl)-1,3-thiazol-2-amine hydrochloride, 3-(Difluoromethyl)-1,2-thiazol-4-amine hydrochloride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C4H5ClF2N2S?

C4H5ClF2N2S has a degree of unsaturation of 2. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.