C53H99N15O12
1 compound has this formula on CompoundList.
- Molar mass
- 1138.47g/mol
- Monoisotopic mass
- 1137.7598Da
- Atoms
- 179
- Elements
- 4
- Rings plus double bonds
- 12
The formula C53H99N15O12 describes a molecule made of 53 carbon atoms, 99 hydrogen atoms, 15 nitrogen atoms and 12 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 5355.92%12.011 × 53 = 636.583 g/mol
- H Hydrogen × 998.77%1.008 × 99 = 99.792 g/mol
- N Nitrogen × 1518.46%14.007 × 15 = 210.105 g/mol
- O Oxygen × 1216.86%15.999 × 12 = 191.988 g/mol
Compounds with the formula C53H99N15O12
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C53H99N15O12?
The molar mass of C53H99N15O12 is 1138.47 g/mol, calculated from standard atomic weights for 53 carbon atoms, 99 hydrogen atoms, 15 nitrogen atoms and 12 oxygen atoms. The monoisotopic mass is 1137.7598 Da.
How many compounds have the formula C53H99N15O12?
CompoundList lists 1 compound with the molecular formula C53H99N15O12, including Cdk5 substrate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C53H99N15O12?
C53H99N15O12 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.