C55H32FN5
1 compound has this formula on CompoundList.
- Molar mass
- 781.89g/mol
- Monoisotopic mass
- 781.2642Da
- Atoms
- 93
- Elements
- 4
- Rings plus double bonds
- 42
The formula C55H32FN5 describes a molecule made of 55 carbon atoms, 32 hydrogen atoms, 1 fluorine atom and 5 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 5584.49%12.011 × 55 = 660.605 g/mol
- H Hydrogen × 324.13%1.008 × 32 = 32.256 g/mol
- F Fluorine × 12.43%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 58.96%14.007 × 5 = 70.035 g/mol
Compounds with the formula C55H32FN5
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C55H32FN5?
The molar mass of C55H32FN5 is 781.89 g/mol, calculated from standard atomic weights for 55 carbon atoms, 32 hydrogen atoms, 1 fluorine atom and 5 nitrogen atoms. The monoisotopic mass is 781.2642 Da.
How many compounds have the formula C55H32FN5?
CompoundList lists 1 compound with the molecular formula C55H32FN5, including 2,3,4,6-Tetrakis(9H-carbazole-9-yl)-5-fluorobenzonitrile. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C55H32FN5?
C55H32FN5 has a degree of unsaturation of 42. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.