C55H62N10
2 compounds have this formula on CompoundList.
- Molar mass
- 863.17g/mol
- Monoisotopic mass
- 862.5159Da
- Atoms
- 127
- Elements
- 3
- Rings plus double bonds
- 30
The formula C55H62N10 describes a molecule made of 55 carbon atoms, 62 hydrogen atoms and 10 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 5576.53%12.011 × 55 = 660.605 g/mol
- H Hydrogen × 627.24%1.008 × 62 = 62.496 g/mol
- N Nitrogen × 1016.23%14.007 × 10 = 140.070 g/mol
Compounds with the formula C55H62N10
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C55H62N10?
The molar mass of C55H62N10 is 863.17 g/mol, calculated from standard atomic weights for 55 carbon atoms, 62 hydrogen atoms and 10 nitrogen atoms. The monoisotopic mass is 862.5159 Da.
How many compounds have the formula C55H62N10?
CompoundList lists 2 compounds with the molecular formula C55H62N10, including Psychotridine, Isopsychotridine A. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C55H62N10?
C55H62N10 has a degree of unsaturation of 30. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.