C56H71N9O23S
4 compounds have this formula on CompoundList.
- Molar mass
- 1270.28g/mol
- Monoisotopic mass
- 1269.4384Da
- Atoms
- 160
- Elements
- 5
- Rings plus double bonds
- 26
The formula C56H71N9O23S describes a molecule made of 56 carbon atoms, 71 hydrogen atoms, 9 nitrogen atoms, 23 oxygen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 5652.95%12.011 × 56 = 672.616 g/mol
- H Hydrogen × 715.63%1.008 × 71 = 71.568 g/mol
- N Nitrogen × 99.92%14.007 × 9 = 126.063 g/mol
- O Oxygen × 2328.97%15.999 × 23 = 367.977 g/mol
- S Sulfur × 12.52%32.06 × 1 = 32.060 g/mol
Compounds with the formula C56H71N9O23S
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 4 of 4 compounds
Frequently asked questions
What is the molar mass of C56H71N9O23S?
The molar mass of C56H71N9O23S is 1270.28 g/mol, calculated from standard atomic weights for 56 carbon atoms, 71 hydrogen atoms, 9 nitrogen atoms, 23 oxygen atoms and 1 sulfur atom. The monoisotopic mass is 1269.4384 Da.
How many compounds have the formula C56H71N9O23S?
CompoundList lists 4 compounds with the molecular formula C56H71N9O23S, including Micafungin, Micafungin impurity F, XV78Dzw9MA. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C56H71N9O23S?
C56H71N9O23S has a degree of unsaturation of 26. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.