CompoundList
Molecular formula

C56H98O35

7 compounds have this formula on CompoundList.

Molar mass
1331.37g/mol
Monoisotopic mass
1330.5889Da
Atoms
189
Elements
3
Rings plus double bonds
8

The formula C56H98O35 describes a molecule made of 56 carbon atoms, 98 hydrogen atoms and 35 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 5650.52%
    12.011 × 56 = 672.616 g/mol
  • H Hydrogen × 987.42%
    1.008 × 98 = 98.784 g/mol
  • O Oxygen × 3542.06%
    15.999 × 35 = 559.965 g/mol
Look up another formula

Compounds with the formula C56H98O35

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 7 of 7 compounds

Frequently asked questions

What is the molar mass of C56H98O35?

The molar mass of C56H98O35 is 1331.37 g/mol, calculated from standard atomic weights for 56 carbon atoms, 98 hydrogen atoms and 35 oxygen atoms. The monoisotopic mass is 1330.5889 Da.

How many compounds have the formula C56H98O35?

CompoundList lists 7 compounds with the molecular formula C56H98O35, including Di-O-methyl-beta-cyclodextrin, 3,6-Di-O-methyl-beta-cyclodextrin, GlyTouCan:G68648GJ. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C56H98O35?

C56H98O35 has a degree of unsaturation of 8. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.