C57H69B3N12O9
1 compound has this formula on CompoundList.
- Molar mass
- 1098.68g/mol
- Monoisotopic mass
- 1098.5590Da
- Atoms
- 150
- Elements
- 5
The formula C57H69B3N12O9 describes a molecule made of 57 carbon atoms, 69 hydrogen atoms, 3 boron atoms, 12 nitrogen atoms and 9 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 5762.31%12.011 × 57 = 684.627 g/mol
- H Hydrogen × 696.33%1.008 × 69 = 69.552 g/mol
- B Boron × 32.95%10.81 × 3 = 32.430 g/mol
- N Nitrogen × 1215.30%14.007 × 12 = 168.084 g/mol
- O Oxygen × 913.11%15.999 × 9 = 143.991 g/mol
Compounds with the formula C57H69B3N12O9
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C57H69B3N12O9?
The molar mass of C57H69B3N12O9 is 1098.68 g/mol, calculated from standard atomic weights for 57 carbon atoms, 69 hydrogen atoms, 3 boron atoms, 12 nitrogen atoms and 9 oxygen atoms. The monoisotopic mass is 1098.5590 Da.
How many compounds have the formula C57H69B3N12O9?
CompoundList lists 1 compound with the molecular formula C57H69B3N12O9, including Bortezomib boronic anhydride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.