CompoundList
Molecular formula

C57H75N9O18

1 compound has this formula on CompoundList.

Molar mass
1174.27g/mol
Monoisotopic mass
1173.5230Da
Atoms
159
Elements
4
Rings plus double bonds
25

The formula C57H75N9O18 describes a molecule made of 57 carbon atoms, 75 hydrogen atoms, 9 nitrogen atoms and 18 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 5758.30%
    12.011 × 57 = 684.627 g/mol
  • H Hydrogen × 756.44%
    1.008 × 75 = 75.600 g/mol
  • N Nitrogen × 910.74%
    14.007 × 9 = 126.063 g/mol
  • O Oxygen × 1824.52%
    15.999 × 18 = 287.982 g/mol
Look up another formula

Compounds with the formula C57H75N9O18

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C57H75N9O18?

The molar mass of C57H75N9O18 is 1174.27 g/mol, calculated from standard atomic weights for 57 carbon atoms, 75 hydrogen atoms, 9 nitrogen atoms and 18 oxygen atoms. The monoisotopic mass is 1173.5230 Da.

How many compounds have the formula C57H75N9O18?

CompoundList lists 1 compound with the molecular formula C57H75N9O18, including Complexe 1656. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C57H75N9O18?

C57H75N9O18 has a degree of unsaturation of 25. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.