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Molecular formula

C58H86N10O26S4

1 compound has this formula on CompoundList.

Molar mass
1467.61g/mol
Monoisotopic mass
1466.4598Da
Atoms
184
Elements
5
Rings plus double bonds
21

The formula C58H86N10O26S4 describes a molecule made of 58 carbon atoms, 86 hydrogen atoms, 10 nitrogen atoms, 26 oxygen atoms and 4 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 5847.47%
    12.011 × 58 = 696.638 g/mol
  • H Hydrogen × 865.91%
    1.008 × 86 = 86.688 g/mol
  • N Nitrogen × 109.54%
    14.007 × 10 = 140.070 g/mol
  • O Oxygen × 2628.34%
    15.999 × 26 = 415.974 g/mol
  • S Sulfur × 48.74%
    32.06 × 4 = 128.240 g/mol
Look up another formula

Compounds with the formula C58H86N10O26S4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

3,3'-{Ethene-1,2-diylbis[(3-sulfo-4,1-phenylene)diazene-2,1-diyl]}bis(6-amino-4-hydroxynaphthalene-2-sulfonic acid)--2,2',2''-nitrilotri(ethan-1-ol) (1/4) chemical structure, C58H86N10O26S4, CAS 75701-34-7
3,3'-{Ethene-1,2-diylbis[(3-sulfo-4,1-phenylene)diazene-2,1-diyl]}bis(6-amino-4-hydroxynaphthalene-2-sulfonic acid)--2,2',2''-nitrilotri(ethan-1-ol) (1/4)
CAS 75701-34-7C58H86N10O26S4

Frequently asked questions

What is the molar mass of C58H86N10O26S4?

The molar mass of C58H86N10O26S4 is 1467.61 g/mol, calculated from standard atomic weights for 58 carbon atoms, 86 hydrogen atoms, 10 nitrogen atoms, 26 oxygen atoms and 4 sulfur atoms. The monoisotopic mass is 1466.4598 Da.

How many compounds have the formula C58H86N10O26S4?

CompoundList lists 1 compound with the molecular formula C58H86N10O26S4, including 3,3'-{Ethene-1,2-diylbis[(3-sulfo-4,1-phenylene)diazene-2,1-diyl]}bis(6-amino-4-hydroxynaphthalene-2-sulfonic acid)--2,2',2''-nitrilotri(ethan-1-ol) (1/4). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C58H86N10O26S4?

C58H86N10O26S4 has a degree of unsaturation of 21. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.