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Molecular formula

C59H97NO14Si

2 compounds have this formula on CompoundList.

Molar mass
1072.50g/mol
Monoisotopic mass
1075.6929Da
Atoms
172
Elements
5
Rings plus double bonds
13

The formula C59H97NO14Si describes a molecule made of 59 carbon atoms, 97 hydrogen atoms, 1 nitrogen atom, 14 oxygen atoms and 1 silicon atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 5966.07%
    12.011 × 59 = 708.649 g/mol
  • H Hydrogen × 979.12%
    1.008 × 97 = 97.776 g/mol
  • N Nitrogen × 11.31%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 1420.88%
    15.999 × 14 = 223.986 g/mol
  • Si Silicon × 12.62%
    28.085 × 1 = 28.085 g/mol
Look up another formula

Compounds with the formula C59H97NO14Si

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

40-O-[2-(t-Butyldimethylsilyl)oxy]ethyl-rapamycin chemical structure, C59H97NO14Si, CAS 159351-68-5
40-O-[2-(t-Butyldimethylsilyl)oxy]ethyl-rapamycin
CAS 159351-68-5C59H97NO14Si
42-O-tert-Butyldimethylsilyloxyethyl-d4 Rapamycin chemical structure, C59H97NO14Si, CAS 1356839-88-7
42-O-tert-Butyldimethylsilyloxyethyl-d4 Rapamycin
CAS 1356839-88-7C59H97NO14Si

Frequently asked questions

What is the molar mass of C59H97NO14Si?

The molar mass of C59H97NO14Si is 1072.50 g/mol, calculated from standard atomic weights for 59 carbon atoms, 97 hydrogen atoms, 1 nitrogen atom, 14 oxygen atoms and 1 silicon atom. The monoisotopic mass is 1075.6929 Da.

How many compounds have the formula C59H97NO14Si?

CompoundList lists 2 compounds with the molecular formula C59H97NO14Si, including 40-O-[2-(t-Butyldimethylsilyl)oxy]ethyl-rapamycin, 42-O-tert-Butyldimethylsilyloxyethyl-d4 Rapamycin. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C59H97NO14Si?

C59H97NO14Si has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.