CompoundList
Molecular formula

C5H2F10

12 compounds have this formula on CompoundList.

Molar mass
252.05g/mol
Monoisotopic mass
251.9997Da
Atoms
17
Elements
3
Rings plus double bonds
0

The formula C5H2F10 describes a molecule made of 5 carbon atoms, 2 hydrogen atoms and 10 fluorine atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 523.83%
    12.011 × 5 = 60.055 g/mol
  • H Hydrogen × 20.80%
    1.008 × 2 = 2.016 g/mol
  • F Fluorine × 1075.37%
    18.998 × 10 = 189.980 g/mol
Look up another formula

Compounds with the formula C5H2F10

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 12 of 12 compounds

Frequently asked questions

What is the molar mass of C5H2F10?

The molar mass of C5H2F10 is 252.05 g/mol, calculated from standard atomic weights for 5 carbon atoms, 2 hydrogen atoms and 10 fluorine atoms. The monoisotopic mass is 251.9997 Da.

How many compounds have the formula C5H2F10?

CompoundList lists 12 compounds with the molecular formula C5H2F10, including 1,1,1,2,2,3,4,5,5,5-Decafluoropentane, 1,1,1,2,2,3,3,4,4,5-Decafluoropentane, rel-(3R,4R)-1,1,1,2,2,3,4,5,5,5-Decafluoropentane. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C5H2F10?

C5H2F10 has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.