C5H3F8I
2 compounds have this formula on CompoundList.
- Molar mass
- 341.96g/mol
- Monoisotopic mass
- 341.9152Da
- Atoms
- 17
- Elements
- 4
- Rings plus double bonds
- 0
The formula C5H3F8I describes a molecule made of 5 carbon atoms, 3 hydrogen atoms, 8 fluorine atoms and 1 iodine atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 517.56%12.011 × 5 = 60.055 g/mol
- H Hydrogen × 30.88%1.008 × 3 = 3.024 g/mol
- F Fluorine × 844.44%18.998 × 8 = 151.984 g/mol
- I Iodine × 137.11%126.9 × 1 = 126.900 g/mol
Compounds with the formula C5H3F8I
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C5H3F8I?
The molar mass of C5H3F8I is 341.96 g/mol, calculated from standard atomic weights for 5 carbon atoms, 3 hydrogen atoms, 8 fluorine atoms and 1 iodine atom. The monoisotopic mass is 341.9152 Da.
How many compounds have the formula C5H3F8I?
CompoundList lists 2 compounds with the molecular formula C5H3F8I, including 1,1,2,2,3,3,4,4-Octafluoro-5-iodopentane, 1,1,1,2,2,5,5,5-Octafluoro-4-iodopentane. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C5H3F8I?
C5H3F8I has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.