C66H93N19O25
1 compound has this formula on CompoundList.
- Molar mass
- 1552.58g/mol
- Monoisotopic mass
- 1551.6590Da
- Atoms
- 203
- Elements
- 4
- Rings plus double bonds
- 30
The formula C66H93N19O25 describes a molecule made of 66 carbon atoms, 93 hydrogen atoms, 19 nitrogen atoms and 25 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 6651.06%12.011 × 66 = 792.726 g/mol
- H Hydrogen × 936.04%1.008 × 93 = 93.744 g/mol
- N Nitrogen × 1917.14%14.007 × 19 = 266.133 g/mol
- O Oxygen × 2525.76%15.999 × 25 = 399.975 g/mol
Compounds with the formula C66H93N19O25
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C66H93N19O25?
The molar mass of C66H93N19O25 is 1552.58 g/mol, calculated from standard atomic weights for 66 carbon atoms, 93 hydrogen atoms, 19 nitrogen atoms and 25 oxygen atoms. The monoisotopic mass is 1551.6590 Da.
How many compounds have the formula C66H93N19O25?
CompoundList lists 1 compound with the molecular formula C66H93N19O25, including Fibrinopeptide B. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C66H93N19O25?
C66H93N19O25 has a degree of unsaturation of 30. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.