C69H81B3F12O3
1 compound has this formula on CompoundList.
- Molar mass
- 1218.81g/mol
- Monoisotopic mass
- 1218.6273Da
- Atoms
- 168
- Elements
- 5
The formula C69H81B3F12O3 describes a molecule made of 69 carbon atoms, 81 hydrogen atoms, 3 boron atoms, 12 fluorine atoms and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 6968.00%12.011 × 69 = 828.759 g/mol
- H Hydrogen × 816.70%1.008 × 81 = 81.648 g/mol
- B Boron × 32.66%10.81 × 3 = 32.430 g/mol
- F Fluorine × 1218.70%18.998 × 12 = 227.976 g/mol
- O Oxygen × 33.94%15.999 × 3 = 47.997 g/mol
Compounds with the formula C69H81B3F12O3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C69H81B3F12O3?
The molar mass of C69H81B3F12O3 is 1218.81 g/mol, calculated from standard atomic weights for 69 carbon atoms, 81 hydrogen atoms, 3 boron atoms, 12 fluorine atoms and 3 oxygen atoms. The monoisotopic mass is 1218.6273 Da.
How many compounds have the formula C69H81B3F12O3?
CompoundList lists 1 compound with the molecular formula C69H81B3F12O3, including 1,3,5-Tris(4-((E)-2-(2,6-di-tert-butylpyrylium-4-yl)vinyl)phenyl)benzene Tetrafluoroborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.