C6H10ClNO3
56 compounds have this formula on CompoundList.
- Molar mass
- 179.60g/mol
- Monoisotopic mass
- 179.0349Da
- Atoms
- 21
- Elements
- 5
- Rings plus double bonds
- 2
The formula C6H10ClNO3 describes a molecule made of 6 carbon atoms, 10 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 640.13%12.011 × 6 = 72.066 g/mol
- H Hydrogen × 105.61%1.008 × 10 = 10.080 g/mol
- Cl Chlorine × 119.74%35.45 × 1 = 35.450 g/mol
- N Nitrogen × 17.80%14.007 × 1 = 14.007 g/mol
- O Oxygen × 326.72%15.999 × 3 = 47.997 g/mol
Compounds with the formula C6H10ClNO3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 56 of 56 compounds
- (2R)-5-Oxo-piperidine-2-carboxylic acid hydrochloride1427203-51-7C6H10ClNO3
- Methyl 3-(2-chloroacetamido)propanoate666832-64-0C6H10ClNO3
- (R)-Methyl 2-(2-chloroacetamido)propanoate153842-01-4C6H10ClNO3
- (3-Oxo-pyrrolidin-1-yl)-acetic acid hydrochloride1187927-10-1C6H10ClNO3
- (s)-5-Oxopiperidine-2-carboxylic acid hcl2718120-86-4C6H10ClNO3
- Methyl 2-oxopyrrolidine-3-carboxylate hydrochloride1242267-85-1C6H10ClNO3
- 2-((2-Chloro-1-oxoethyl)amino)ethyl acetate93783-16-5C6H10ClNO3
- N-(4-Chlorobutanoyl)glycine64026-50-2C6H10ClNO3
- Propan-2-yl (chloroacetyl)carbamate13558-72-0C6H10ClNO3
- Butanoic acid, 2-[(chloroacetyl)amino]-, (R)-121786-32-1C6H10ClNO3
- (3aR,6aS)-5-Amino-hexahydrocyclopenta[d][1,3]dioxol-2-one hydrochloride2361578-40-5C6H10ClNO3
- 2-[(3S)-2-Oxopyrrolidin-3-yl]acetic acid hydrochloride2490314-54-8C6H10ClNO3
- tert-Butyl (2Z)-2-chloro-2-hydroxyiminoacetate199169-85-2C6H10ClNO3
- Methyl (chlorocarbonyl)propan-2-ylcarbamate19265-16-8C6H10ClNO3
- N-Hydroxy-2,2-dimethyl-1,3-dioxolane-4-carboximidoyl chloride90137-19-2C6H10ClNO3
- tert-Butyl 2-chloro-2-(hydroxyimino)acetateC6H10ClNO3
- 6,8-Dioxa-2-azaspiro[3.5]nonan-7-one hydrochloride2097999-74-9C6H10ClNO3
- 2-Amino-2-(3-oxocyclobutyl)acetic acid hydrochloride2097949-03-4C6H10ClNO3
- (R)-4-Oxopiperidine-2-carboxylic acid hydrochloride2306253-32-5C6H10ClNO3
- Ethyl (2-chloropropanoyl)carbamate24224-09-7C6H10ClNO3
- 4-Chloro-2-acetamidobutanoic acid1822564-67-9C6H10ClNO3
- H-Pyr-OMe hydrochloride2011775-31-6C6H10ClNO3
- 2-(1,3-Oxazolidin-3-yl)ethyl carbonochloridate2172095-83-7C6H10ClNO3
- (4S)-4-Amino-6-chloro-5-oxohexanoic acid61389-57-9C6H10ClNO3
- (4R)-4-Amino-6-chloro-5-oxohexanoic acid61389-56-8C6H10ClNO3
- 1-Chloroethyl N-acetyl-N-methylcarbamate338990-22-0C6H10ClNO3
- Methyl 3-[(chlorocarbonyl)(methyl)amino]propanoate39617-41-9C6H10ClNO3
- 2-(2-Oxopyrrolidin-3-yl)acetic Acid Hydrochloride3079683-35-2C6H10ClNO3
- Methyl 4-oxopyrrolidine-3-carboxylate hydrochloride1780849-38-8C6H10ClNO3
- Methyl N-(4-chloro-3-oxobutyl)carbamate67937-81-9C6H10ClNO3
- Methyl (R)-5-oxopyrrolidine-2-carboxylate hydrochloride835915-17-8C6H10ClNO3
- Methyl 3,6-dihydro-2H-1,2-oxazine-4-carboxylate hydrochloride3028155-07-6C6H10ClNO3
Frequently asked questions
What is the molar mass of C6H10ClNO3?
The molar mass of C6H10ClNO3 is 179.60 g/mol, calculated from standard atomic weights for 6 carbon atoms, 10 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 3 oxygen atoms. The monoisotopic mass is 179.0349 Da.
How many compounds have the formula C6H10ClNO3?
CompoundList lists 56 compounds with the molecular formula C6H10ClNO3, including Methyl 2-(acetylamino)-3-chloropropionate, Ethyl 2-(2-chloroacetamido)acetate, Chloromethyl 4-morpholinecarboxylate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C6H10ClNO3?
C6H10ClNO3 has a degree of unsaturation of 2. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.