CompoundList
Molecular formula

C6H11BF3KO2

4 compounds have this formula on CompoundList.

Molar mass
222.05g/mol
Monoisotopic mass
222.0441Da
Atoms
24
Elements
6

The formula C6H11BF3KO2 describes a molecule made of 6 carbon atoms, 11 hydrogen atoms, 1 boron atom, 3 fluorine atoms, 1 potassium atom and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 632.45%
    12.011 × 6 = 72.066 g/mol
  • H Hydrogen × 114.99%
    1.008 × 11 = 11.088 g/mol
  • B Boron × 14.87%
    10.81 × 1 = 10.810 g/mol
  • F Fluorine × 325.67%
    18.998 × 3 = 56.994 g/mol
  • K Potassium × 117.61%
    39.098 × 1 = 39.098 g/mol
  • O Oxygen × 214.41%
    15.999 × 2 = 31.998 g/mol
Look up another formula

Compounds with the formula C6H11BF3KO2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 4 of 4 compounds

Frequently asked questions

What is the molar mass of C6H11BF3KO2?

The molar mass of C6H11BF3KO2 is 222.05 g/mol, calculated from standard atomic weights for 6 carbon atoms, 11 hydrogen atoms, 1 boron atom, 3 fluorine atoms, 1 potassium atom and 2 oxygen atoms. The monoisotopic mass is 222.0441 Da.

How many compounds have the formula C6H11BF3KO2?

CompoundList lists 4 compounds with the molecular formula C6H11BF3KO2, including Potassium trifluoro(5-methoxy-5-oxopentyl)boranuide, Potassium trifluoro[(oxan-4-yloxy)methyl]boranuide, Potassium(4-ethoxy-4-oxobutan-2-yl)trifluoroboranuide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.