C6H4BF3IK
3 compounds have this formula on CompoundList.
- Molar mass
- 309.90g/mol
- Monoisotopic mass
- 309.9040Da
- Atoms
- 16
- Elements
- 6
The formula C6H4BF3IK describes a molecule made of 6 carbon atoms, 4 hydrogen atoms, 1 boron atom, 3 fluorine atoms, 1 iodine atom and 1 potassium atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 623.25%12.011 × 6 = 72.066 g/mol
- H Hydrogen × 41.30%1.008 × 4 = 4.032 g/mol
- B Boron × 13.49%10.81 × 1 = 10.810 g/mol
- F Fluorine × 318.39%18.998 × 3 = 56.994 g/mol
- I Iodine × 140.95%126.9 × 1 = 126.900 g/mol
- K Potassium × 112.62%39.098 × 1 = 39.098 g/mol
Compounds with the formula C6H4BF3IK
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
Frequently asked questions
What is the molar mass of C6H4BF3IK?
The molar mass of C6H4BF3IK is 309.90 g/mol, calculated from standard atomic weights for 6 carbon atoms, 4 hydrogen atoms, 1 boron atom, 3 fluorine atoms, 1 iodine atom and 1 potassium atom. The monoisotopic mass is 309.9040 Da.
How many compounds have the formula C6H4BF3IK?
CompoundList lists 3 compounds with the molecular formula C6H4BF3IK, including Potassium 4-iodophenyltrifluoroborate, Potassium 3-iodophenyltrifluoroborate, Potassium 2-iodophenyltrifluoroborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.