C71H94ClN19O13
1 compound has this formula on CompoundList.
- Molar mass
- 1457.10g/mol
- Monoisotopic mass
- 1455.6967Da
- Atoms
- 198
- Elements
- 5
- Rings plus double bonds
- 34
The formula C71H94ClN19O13 describes a molecule made of 71 carbon atoms, 94 hydrogen atoms, 1 chlorine atom, 19 nitrogen atoms and 13 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 7158.53%12.011 × 71 = 852.781 g/mol
- H Hydrogen × 946.50%1.008 × 94 = 94.752 g/mol
- Cl Chlorine × 12.43%35.45 × 1 = 35.450 g/mol
- N Nitrogen × 1918.26%14.007 × 19 = 266.133 g/mol
- O Oxygen × 1314.27%15.999 × 13 = 207.987 g/mol
Compounds with the formula C71H94ClN19O13
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C71H94ClN19O13?
The molar mass of C71H94ClN19O13 is 1457.10 g/mol, calculated from standard atomic weights for 71 carbon atoms, 94 hydrogen atoms, 1 chlorine atom, 19 nitrogen atoms and 13 oxygen atoms. The monoisotopic mass is 1455.6967 Da.
How many compounds have the formula C71H94ClN19O13?
CompoundList lists 1 compound with the molecular formula C71H94ClN19O13, including LHRH, N-ac-Trp(1)-(4-Cl-phe)(2)-trp(3)-arg(6)-ala(10)-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C71H94ClN19O13?
C71H94ClN19O13 has a degree of unsaturation of 34. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.