C7H6BFN4O2
1 compound has this formula on CompoundList.
- Molar mass
- 207.96g/mol
- Monoisotopic mass
- 208.0568Da
- Atoms
- 21
- Elements
- 6
The formula C7H6BFN4O2 describes a molecule made of 7 carbon atoms, 6 hydrogen atoms, 1 boron atom, 1 fluorine atom, 4 nitrogen atoms and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 740.43%12.011 × 7 = 84.077 g/mol
- H Hydrogen × 62.91%1.008 × 6 = 6.048 g/mol
- B Boron × 15.20%10.81 × 1 = 10.810 g/mol
- F Fluorine × 19.14%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 426.94%14.007 × 4 = 56.028 g/mol
- O Oxygen × 215.39%15.999 × 2 = 31.998 g/mol
Compounds with the formula C7H6BFN4O2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C7H6BFN4O2?
The molar mass of C7H6BFN4O2 is 207.96 g/mol, calculated from standard atomic weights for 7 carbon atoms, 6 hydrogen atoms, 1 boron atom, 1 fluorine atom, 4 nitrogen atoms and 2 oxygen atoms. The monoisotopic mass is 208.0568 Da.
How many compounds have the formula C7H6BFN4O2?
CompoundList lists 1 compound with the molecular formula C7H6BFN4O2, including 4-Fluoro-3-(tetrazol-5-yl)phenylboronic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.