C7H7BF4
1 compound has this formula on CompoundList.
- Molar mass
- 177.94g/mol
- Monoisotopic mass
- 178.0577Da
- Atoms
- 19
- Elements
- 4
The formula C7H7BF4 describes a molecule made of 7 carbon atoms, 7 hydrogen atoms, 1 boron atom and 4 fluorine atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 747.25%12.011 × 7 = 84.077 g/mol
- H Hydrogen × 73.97%1.008 × 7 = 7.056 g/mol
- B Boron × 16.08%10.81 × 1 = 10.810 g/mol
- F Fluorine × 442.71%18.998 × 4 = 75.992 g/mol
Compounds with the formula C7H7BF4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C7H7BF4?
The molar mass of C7H7BF4 is 177.94 g/mol, calculated from standard atomic weights for 7 carbon atoms, 7 hydrogen atoms, 1 boron atom and 4 fluorine atoms. The monoisotopic mass is 178.0577 Da.
How many compounds have the formula C7H7BF4?
CompoundList lists 1 compound with the molecular formula C7H7BF4, including Cycloheptatrienylium, tetrafluoroborate(1-) (1:1). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.