CompoundList
Molecular formula

C7H9BF5KO

1 compound has this formula on CompoundList.

Molar mass
254.05g/mol
Monoisotopic mass
254.0304Da
Atoms
24
Elements
6

The formula C7H9BF5KO describes a molecule made of 7 carbon atoms, 9 hydrogen atoms, 1 boron atom, 5 fluorine atoms, 1 potassium atom and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 733.10%
    12.011 × 7 = 84.077 g/mol
  • H Hydrogen × 93.57%
    1.008 × 9 = 9.072 g/mol
  • B Boron × 14.26%
    10.81 × 1 = 10.810 g/mol
  • F Fluorine × 537.39%
    18.998 × 5 = 94.990 g/mol
  • K Potassium × 115.39%
    39.098 × 1 = 39.098 g/mol
  • O Oxygen × 16.30%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C7H9BF5KO

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C7H9BF5KO?

The molar mass of C7H9BF5KO is 254.05 g/mol, calculated from standard atomic weights for 7 carbon atoms, 9 hydrogen atoms, 1 boron atom, 5 fluorine atoms, 1 potassium atom and 1 oxygen atom. The monoisotopic mass is 254.0304 Da.

How many compounds have the formula C7H9BF5KO?

CompoundList lists 1 compound with the molecular formula C7H9BF5KO, including Potassium (2,2-difluoro-6-oxaspiro(2.5)octan-1-yl)trifluoroboranuide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.