C88H97Cl2N9O33
6 compounds have this formula on CompoundList.
- Molar mass
- 1879.67g/mol
- Monoisotopic mass
- 1877.5566Da
- Atoms
- 229
- Elements
- 5
- Rings plus double bonds
- 44
The formula C88H97Cl2N9O33 describes a molecule made of 88 carbon atoms, 97 hydrogen atoms, 2 chlorine atoms, 9 nitrogen atoms and 33 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 8856.23%12.011 × 88 = 1056.968 g/mol
- H Hydrogen × 975.20%1.008 × 97 = 97.776 g/mol
- Cl Chlorine × 23.77%35.45 × 2 = 70.900 g/mol
- N Nitrogen × 96.71%14.007 × 9 = 126.063 g/mol
- O Oxygen × 3328.09%15.999 × 33 = 527.967 g/mol
Compounds with the formula C88H97Cl2N9O33
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 6 of 6 compounds
Frequently asked questions
What is the molar mass of C88H97Cl2N9O33?
The molar mass of C88H97Cl2N9O33 is 1879.67 g/mol, calculated from standard atomic weights for 88 carbon atoms, 97 hydrogen atoms, 2 chlorine atoms, 9 nitrogen atoms and 33 oxygen atoms. The monoisotopic mass is 1877.5566 Da.
How many compounds have the formula C88H97Cl2N9O33?
CompoundList lists 6 compounds with the molecular formula C88H97Cl2N9O33, including Teicoplanin, Teicoplanin A2-3, Teicoplanin A2-2. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C88H97Cl2N9O33?
C88H97Cl2N9O33 has a degree of unsaturation of 44. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.