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Molecular formula

C98H138N24O33

2 compounds have this formula on CompoundList.

Molar mass
2180.32g/mol
Monoisotopic mass
2178.9858Da
Atoms
293
Elements
4
Rings plus double bonds
42

The formula C98H138N24O33 describes a molecule made of 98 carbon atoms, 138 hydrogen atoms, 24 nitrogen atoms and 33 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 9853.99%
    12.011 × 98 = 1177.078 g/mol
  • H Hydrogen × 1386.38%
    1.008 × 138 = 139.104 g/mol
  • N Nitrogen × 2415.42%
    14.007 × 24 = 336.168 g/mol
  • O Oxygen × 3324.22%
    15.999 × 33 = 527.967 g/mol
Look up another formula

Compounds with the formula C98H138N24O33

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Bivalirudin chemical structure, C98H138N24O33, CAS 128270-60-0
Bivalirudin
CAS 128270-60-0C98H138N24O33
H-DL-Phe-DL-Pro-DL-Arg-DL-Pro-Gly-Gly-Gly-Gly-DL-Asn-Gly-DL-Asp-DL-Phe-DL-Glu-DL-Glu-xiIle-DL-Pro-DL-Glu-DL-Glu-DL-Tyr-DL-Leu-OH chemical structure, C98H138N24O33
H-DL-Phe-DL-Pro-DL-Arg-DL-Pro-Gly-Gly-Gly-Gly-DL-Asn-Gly-DL-Asp-DL-Phe-DL-Glu-DL-Glu-xiIle-DL-Pro-DL-Glu-DL-Glu-DL-Tyr-DL-Leu-OH
C98H138N24O33

Frequently asked questions

What is the molar mass of C98H138N24O33?

The molar mass of C98H138N24O33 is 2180.32 g/mol, calculated from standard atomic weights for 98 carbon atoms, 138 hydrogen atoms, 24 nitrogen atoms and 33 oxygen atoms. The monoisotopic mass is 2178.9858 Da.

How many compounds have the formula C98H138N24O33?

CompoundList lists 2 compounds with the molecular formula C98H138N24O33, including Bivalirudin, H-DL-Phe-DL-Pro-DL-Arg-DL-Pro-Gly-Gly-Gly-Gly-DL-Asn-Gly-DL-Asp-DL-Phe-DL-Glu-DL-Glu-xiIle-DL-Pro-DL-Glu-DL-Glu-DL-Tyr-DL-Leu-OH. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C98H138N24O33?

C98H138N24O33 has a degree of unsaturation of 42. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.